19x^2-29x+10=

Solution for 19x^2-29x+10= equation:

Simplifying
19x2 + -29x + 10 = 0

Reorder the terms:
10 + -29x + 19x2 = 0

Solving
10 + -29x + 19x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(10 + -19x)(1 + -1x) = 0

Subproblem 1
Set the factor '(10 + -19x)' equal to zero and attempt to solve:

Simplifying
10 + -19x = 0

Solving
10 + -19x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -19x = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -19x = 0 + -10
-19x = 0 + -10

Combine like terms: 0 + -10 = -10
-19x = -10

Divide each side by '-19'.
x = 0.5263157895

Simplifying
x = 0.5263157895
Subproblem 2
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Solution
x = {0.5263157895, 1}